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@ -21,7 +21,7 @@ TODO:
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\unify{}'s type solutions for a constraint set generated by $\typeExpr{}$ are correct.
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\begin{description}
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\item[if] $\typeExpr{}(\mtypeEnvironment{}, \texttt{e}, \tv{a}) = C$
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and $(\Delta, \sigma) = \unify{\Delta', C}$
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and $(\Delta, \sigma) = \unify{}(\Delta', C)$
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% , with $C = \set{ \overline{ \type{S} \lessdot \type{T} } \cup \overline{ \type{S'} \lessdotCC \type{T'} } }$
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% and $\vdash \ol{L} : \mtypeEnvironment{}$
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% and $\Gamma \subseteq \mtypeEnvironment{}$
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@ -63,6 +63,12 @@ By structural induction over the expression $\texttt{e}$.
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$\text{dom}(\Delta_c) \subseteq \text{fv}{\type{N}}$ by lemma \ref{lemma:tvsNoFV}.
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% X.List<X> <. List<a?>
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% $\sigma(\ol{\tv{r}}) = \overline{\wcNtype{\Delta}{N}}$,
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% $\ol{N} <: [\ol{S}/\ol{X}]\ol{U}$,
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% TODO: S ok? We could proof $\Delta, \Delta' \overline{\Delta} \vdash \ol{S} \ \ok$
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% by proofing every substitution in Unify is ok aslong as every type in the inputs is ok
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$\Delta \vdash \sigma(\tv{a}), \wcNtype{\Delta_c}{N} \ \ok$ %TODO
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%Easy, because unify only generates substitutions for normal type placeholders which are OK
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