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8059455: LambdaForm.prepare() does unnecessary work for cached LambdaForms

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Reviewed-by: psandoz
This commit is contained in:
Vladimir Ivanov 2015-04-23 18:01:38 +03:00
parent 476d962701
commit 7840b0e7c1
1 changed files with 3 additions and 3 deletions
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6
jdk/src/java.base/share/classes/java/lang/invoke/LambdaForm.java
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@ -631,7 +631,7 @@ class LambdaForm {
* as a sort of pre-invocation linkage step.)
*/
public void prepare() {
if (COMPILE_THRESHOLD == 0) {
if (COMPILE_THRESHOLD == 0 && !isCompiled) {
compileToBytecode();
}
if (this.vmentry != null) {
@ -645,11 +645,11 @@ class LambdaForm {
/** Generate optimizable bytecode for this form. */
MemberName compileToBytecode() {
MethodType invokerType = methodType();
assert(vmentry == null || vmentry.getMethodType().basicType().equals(invokerType));
if (vmentry != null && isCompiled) {
return vmentry; // already compiled somehow
}
MethodType invokerType = methodType();
assert(vmentry == null || vmentry.getMethodType().basicType().equals(invokerType));
try {
vmentry = InvokerBytecodeGenerator.generateCustomizedCode(this, invokerType);
if (TRACE_INTERPRETER)