8236769: Clarify javadoc of memory access API
Reviewed-by: chegar
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@ -74,7 +74,13 @@ public interface MemoryAddress {
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/**
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* Compares the specified object with this address for equality. Returns {@code true} if and only if the specified
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* object is also a address, and it is equal to this address.
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* object is also an address, and it refers to the same memory location as this address.
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*
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* @apiNote two addresses might be considered equal despite their associated segments differ. This
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* can happen, for instance, if the segment associated with one address is a <em>slice</em>
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* (see {@link MemorySegment#asSlice(long, long)}) of the segment associated with the other address. Moreover,
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* two addresses might be considered equals despite differences in the temporal bounds associated with their
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* corresponding segments (this is possible, for example, as a result of calls to {@link MemorySegment#acquire()}).
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*
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* @param that the object to be compared for equality with this address.
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* @return {@code true} if the specified object is equal to this address.
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@ -55,14 +55,14 @@ import java.util.OptionalLong;
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* <p>
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* Non-platform classes should not implement {@linkplain MemoryLayout} directly.
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*
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* <h2>Size, alignment and byte order</h2>
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* <h2><a id = "layout-align">Size, alignment and byte order</a></h2>
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*
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* All layouts have a size; layout size for value and padding layouts is always explicitly denoted; this means that a layout description
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* always has the same size in bits, regardless of the platform in which it is used. For derived layouts, the size is computed
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* as follows:
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* <ul>
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* <li>for a <em>finite</em> sequence layout <em>S</em> whose element layout is <em>E</em> and size is L,
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* the size of <em>S</em> is that of <em>E, multiplied by L</em></li>
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* the size of <em>S</em> is that of <em>E</em>, multiplied by <em>L</em></li>
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* <li>the size of an <em>unbounded</em> sequence layout is <em>unknown</em></li>
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* <li>for a group layout <em>G</em> with member layouts <em>M1</em>, <em>M2</em>, ... <em>Mn</em> whose sizes are
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* <em>S1</em>, <em>S2</em>, ... <em>Sn</em>, respectively, the size of <em>G</em> is either <em>S1 + S2 + ... + Sn</em> or
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@ -180,6 +180,9 @@ public interface MemoryLayout extends Constable {
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* <li>{@code A=512} is the most strict alignment required by the x86/SV ABI (for AVX-512 data).</li>
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* </ul>
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*
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* If no explicit alignment constraint was set on this layout (see {@link #withBitAlignment(long)}),
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* then this method returns the <a href="#layout-align">natural alignment</a> constraint (in bits) associated with this layout.
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*
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* @return the layout alignment constraint, in bits.
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*/
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long bitAlignment();
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@ -195,6 +198,9 @@ public interface MemoryLayout extends Constable {
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* <li>{@code A=64} is the most strict alignment required by the x86/SV ABI (for AVX-512 data).</li>
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* </ul>
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*
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* If no explicit alignment constraint was set on this layout (see {@link #withBitAlignment(long)}),
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* then this method returns the <a href="#layout-align">natural alignment</a> constraint (in bytes) associated with this layout.
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*
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* @return the layout alignment constraint, in bytes.
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* @throws UnsupportedOperationException if {@code bitAlignment()} is not a multiple of 8.
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*/
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@ -352,7 +358,16 @@ E * (S + I * F)
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/**
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* Compares the specified object with this layout for equality. Returns {@code true} if and only if the specified
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* object is also a layout, and it is equal to this layout.
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* object is also a layout, and it is equal to this layout. Two layouts are considered equal if they are of
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* the same kind, have the same size, name and alignment constraints. Furthermore, depending on the layout kind, additional
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* conditions must be satisfied:
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* <ul>
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* <li>two value layouts are considered equal if they have the same endianness (see {@link ValueLayout#order()})</li>
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* <li>two sequence layouts are considered equal if they have the same element count (see {@link SequenceLayout#elementCount()}), and
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* if their element layouts (see {@link SequenceLayout#elementLayout()}) are also equal</li>
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* <li>two group layouts are considered equal if they are of the same kind (see {@link GroupLayout#isStruct()},
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* {@link GroupLayout#isUnion()}) and if their member layouts (see {@link GroupLayout#memberLayouts()}) are also equal</li>
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* </ul>
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*
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* @param that the object to be compared for equality with this layout.
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* @return {@code true} if the specified object is equal to this layout.
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54
test/jdk/java/foreign/TestTypeAccess.java
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54
test/jdk/java/foreign/TestTypeAccess.java
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@ -0,0 +1,54 @@
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/*
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* Copyright (c) 2019, Oracle and/or its affiliates. All rights reserved.
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* DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
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*
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* This code is free software; you can redistribute it and/or modify it
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* under the terms of the GNU General Public License version 2 only, as
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* published by the Free Software Foundation.
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*
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* This code is distributed in the hope that it will be useful, but WITHOUT
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* ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
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* FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License
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* version 2 for more details (a copy is included in the LICENSE file that
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* accompanied this code).
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*
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* You should have received a copy of the GNU General Public License version
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* 2 along with this work; if not, write to the Free Software Foundation,
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* Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
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*
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* Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
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* or visit www.oracle.com if you need additional information or have any
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* questions.
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*
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*/
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/*
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* @test
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* @run testng TestTypeAccess
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*/
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import jdk.incubator.foreign.MemorySegment;
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import jdk.incubator.foreign.MemoryLayouts;
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import org.testng.annotations.*;
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import java.lang.invoke.VarHandle;
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import java.lang.invoke.WrongMethodTypeException;
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public class TestTypeAccess {
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static final VarHandle INT_HANDLE = MemoryLayouts.JAVA_INT.varHandle(int.class);
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@Test(expectedExceptions=ClassCastException.class)
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public void testMemoryAddressCoordinateAsString() {
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try (MemorySegment s = MemorySegment.allocateNative(8)) {
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int v = (int)INT_HANDLE.get("string");
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}
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}
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@Test(expectedExceptions=WrongMethodTypeException.class)
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public void testMemoryCoordinatePrimitive() {
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try (MemorySegment s = MemorySegment.allocateNative(8)) {
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int v = (int)INT_HANDLE.get(1);
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}
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}
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}
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