/* * Copyright (c) 2014, Oracle and/or its affiliates. All rights reserved. * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER. * * This code is free software; you can redistribute it and/or modify it * under the terms of the GNU General Public License version 2 only, as * published by the Free Software Foundation. * * This code is distributed in the hope that it will be useful, but WITHOUT * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License * version 2 for more details (a copy is included in the LICENSE file that * accompanied this code). * * You should have received a copy of the GNU General Public License version * 2 along with this work; if not, write to the Free Software Foundation, * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA. * * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA * or visit www.oracle.com if you need additional information or have any * questions. */ /** * JDK-8060011: Concatenating an array and converting it to Java gives wrong result * * @test * @run */ function compareAsJavaArrays(a1, a2) { var ja1 = Java.to(a1); var ja2 = Java.to(a2); if (ja1.length !== ja2.length) { throw "different length"; } for (var i = 0; i < ja1.length; i++) { if (ja1[i] !== ja2[i]) { throw "different element at " + i; } } if (java.util.Arrays.toString(ja1) !== java.util.Arrays.toString(ja2)) { throw "different string representation"; } } compareAsJavaArrays([0, 1, 2, 3], [0].concat([1, 2, 3])); compareAsJavaArrays([1000000000, 2000000000, 3000000000, 4000000000], [1000000000].concat([2000000000, 3000000000, 4000000000])); compareAsJavaArrays([0.5, 1.5, 2.5, 3.5], [0.5].concat([1.5, 2.5, 3.5])); compareAsJavaArrays(["0", "1", "2", "3"], ["0"].concat(["1", "2", "3"]));