/* * Copyright (c) 2017, Oracle and/or its affiliates. All rights reserved. * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER. * * This code is free software; you can redistribute it and/or modify it * under the terms of the GNU General Public License version 2 only, as * published by the Free Software Foundation. * * This code is distributed in the hope that it will be useful, but WITHOUT * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License * version 2 for more details (a copy is included in the LICENSE file that * accompanied this code). * * You should have received a copy of the GNU General Public License version * 2 along with this work; if not, write to the Free Software Foundation, * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA. * * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA * or visit www.oracle.com if you need additional information or have any * questions. */ /* * @test * @bug 8186654 * @summary Transpositions of an array result in the same * EqualByteArray.hashCode() * @modules java.base/sun.security.util */ import sun.security.util.Cache; public class EbaHash { public static void main(String[] args) throws Throwable { int h1 = new Cache.EqualByteArray(new byte[] {1,2,3}).hashCode(); int h2 = new Cache.EqualByteArray(new byte[] {2,3,1}).hashCode(); int h3 = new Cache.EqualByteArray(new byte[] {3,1,2}).hashCode(); if (h1 == h2 && h2 == h3) { throw new RuntimeException("Transpositions of an array" + " resulted in the same hashCode()"); } } }