/* * Copyright (c) 2002, 2018, Oracle and/or its affiliates. All rights reserved. * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER. * * This code is free software; you can redistribute it and/or modify it * under the terms of the GNU General Public License version 2 only, as * published by the Free Software Foundation. * * This code is distributed in the hope that it will be useful, but WITHOUT * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License * version 2 for more details (a copy is included in the LICENSE file that * accompanied this code). * * You should have received a copy of the GNU General Public License version * 2 along with this work; if not, write to the Free Software Foundation, * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA. * * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA * or visit www.oracle.com if you need additional information or have any * questions. */ package nsk.share; import java.util.*; import java.util.regex.*; /** * Weak emulator of perl's grep function with very small functionality. * This class does not use java.util.regexp classes which appear in * JDK1.4 API. * * @see Grep */ public class Paragrep { String[] stringArray; /** * Takes String array as character sequence for matching the pattern. */ public Paragrep (String[] stringArray) { this.stringArray = stringArray; } /** * Returns number of non-interleaved occurences of the pattern string. */ public int find (String pattern) { if (pattern.length() == 0) { throw new Failure("Empty string as input parameter for Grep.find(pattern) method"); } int counter = 0; for (int i = 0; i < stringArray.length; i++) { String string = stringArray[i]; if (string != null) { // Find all non-interleaved occurences of pattern in this string for (int ind = 0; ind < string.length(); ) { int k = 0; if ((k = string.indexOf(pattern, ind)) >= 0) { counter++; ind = k + pattern.length(); } else { break; } } } } return counter; } /** * Returns all string in stringArray which have * occurences of the pattern string. */ public String[] findStrings (String pattern) { if (pattern.length() == 0) { throw new Failure("Empty string as input parameter for Grep.find(pattern) method"); } Vector v = new Vector(); for (int i = 0; i < stringArray.length; i++) { String string = stringArray[i]; if (string != null && string.indexOf(pattern) >= 0) { v.add(string); } } String[] result = new String[v.size()]; v.toArray(result); return result; } /** * Returns first string of stringArray which contains * the pattern string or empty string othrewise. */ public String findFirst (String pattern) { if (pattern.length() == 0) { throw new Failure("Empty string as input parameter for Paragrep.findFirst(pattern) method"); } String result = ""; for (int i = 0; i < stringArray.length; i++) { String string = stringArray[i]; if (string != null) { if (string.indexOf(pattern) >= 0) { result = string; break; } } } return result; } /** * Returns first string of stringArray which contains * all of the pattern strings or empty string otherwise. */ public String findFirst (Vector patternVector) { if (patternVector.isEmpty()) { throw new Failure("Empty vector as input parameter for Paragrep.findFirst(patternVector) method"); } String[] patterns = new String[patternVector.size()]; patternVector.toArray(patterns); String result = ""; for (int i = 0; i < stringArray.length; i++) { String string = stringArray[i]; if (string != null && string.length() > 0) { for (int j = 0; j < patterns.length; j++) { String pattern = patterns[j]; if (string.indexOf(pattern) >= 0) { if (j + 1 == patterns.length) { // found all patterns in the current string result = string; i = stringArray.length; } } else { break; } } } } return result; } /** * Returns count of strings in stringArray which contain * all of the pattern strings. */ public int find (Vector patternVector) { if (patternVector.isEmpty()) { throw new Failure("Empty vector as input parameter for Paragrep.find(patternVector) method"); } String[] patterns = new String[patternVector.size()]; patternVector.toArray(patterns); int counter = 0; for (int i = 0; i < stringArray.length; i++) { String string = stringArray[i]; if (string != null && string.length() > 0) { for (int j = 0; j < patterns.length; j++) { String pattern = patterns[j]; if (string.indexOf(pattern) >= 0) { if (j + 1 == patterns.length) { // found all patterns in the current string counter++; } } else { break; } } } } return counter; } }