3789983e89
Reviewed-by: darcy, ihse
51 lines
1.7 KiB
Java
51 lines
1.7 KiB
Java
/*
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* Copyright (c) 2002, Oracle and/or its affiliates. All rights reserved.
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* DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
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*
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* This code is free software; you can redistribute it and/or modify it
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* under the terms of the GNU General Public License version 2 only, as
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* published by the Free Software Foundation.
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*
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* This code is distributed in the hope that it will be useful, but WITHOUT
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* ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
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* FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License
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* version 2 for more details (a copy is included in the LICENSE file that
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* accompanied this code).
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*
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* You should have received a copy of the GNU General Public License version
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* 2 along with this work; if not, write to the Free Software Foundation,
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* Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
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*
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* Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
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* or visit www.oracle.com if you need additional information or have any
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* questions.
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*/
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/*
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* @test
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* @bug 4403168
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* @summary Verify correct type of result of ?: operator when constant folding occurs
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* @author gafter
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*
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* @run main FoldConditional
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*/
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public class FoldConditional {
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static void f(double x) {
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// OK
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}
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static void f(int x) {
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throw new Error();
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}
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public static void main(String args[]){
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int x=5;
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String value0 = ("value is " + 9.0).intern();
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String value1 = ("value is " + ((x> 4)?9:9.9)).intern();
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String value2 = ("value is " + ( true ? 9 : (9.9+x) )).intern();
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f(true ? 9 : 9.9);
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f(true ? 9 : (9.9 + x));
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if (value0 != value1) throw new Error();
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if (value0 != value2) throw new Error();
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}
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}
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