835c863ba8
Correcting handling of boolean-valued switch expressions when true/false; generating them directly rather than desugaring in Lower. Reviewed-by: mcimadamore
88 lines
1.9 KiB
Java
88 lines
1.9 KiB
Java
/**
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* @test /nodynamiccopyright/
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* @bug 8214031
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* @summary Verify that definite assignment when true works (illegal code)
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* @compile/fail/ref=DefiniteAssignment2.out --enable-preview --source 12 -XDrawDiagnostics DefiniteAssignment2.java
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*/
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public class DefiniteAssignment2 {
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public static void main(String[] args) {
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int a = 0;
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boolean b = true;
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boolean t;
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{
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int x;
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t = (b && switch(a) {
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case 0: break (x = 1) == 1 || true;
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default: break false;
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}) || x == 1;
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}
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{
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int x;
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t = (switch(a) {
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case 0: break (x = 1) == 1;
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default: break false;
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}) || x == 1;
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}
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{
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int x;
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t = (switch(a) {
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case 0: x = 1; break true;
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case 1: break (x = 1) == 1;
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default: break false;
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}) || x == 1;
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}
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{
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int x;
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t = (switch(a) {
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case 0: break true;
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case 1: break (x = 1) == 1;
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default: break false;
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}) && x == 1;
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}
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{
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int x;
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t = (switch(a) {
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case 0: break false;
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case 1: break isTrue() || (x = 1) == 1;
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default: break false;
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}) && x == 1;
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}
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{
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int x;
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t = (switch(a) {
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case 0: break false;
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case 1: break isTrue() ? true : (x = 1) == 1;
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default: break false;
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}) && x == 1;
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}
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{
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final int x;
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t = (switch(a) {
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case 0: break false;
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case 1: break isTrue() ? true : (x = 1) == 1;
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default: break false;
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}) && (x = 1) == 1;
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}
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}
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private static boolean isTrue() {
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return true;
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}
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}
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