Soundness Prepare
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@ -272,24 +272,29 @@ $\Delta \vdash \sigma(C') \implies \Delta \vdash \sigma(C)$
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\item[Prepare]
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To show
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$\Delta \vdash \wctype{\overline{\wildcard{B}{\type{U'}}{\type{L'}}}}{C}{\ol{S}} <: \wctype{\overline{\wildcard{A}{\type{U}}{\type{L}}}}{C}{\ol{T}}$ by S-Exists we have to proof:
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We know
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\begin{gather}
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\ol{S} = \ol{T}\\
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\text{fv}(\wctype{\overline{\wildcard{B}{\type{U'}}{\type{L'}}}}{C}{\ol{S}}) = \emptyset\\
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\text{fv}(\wctype{\overline{\wildcard{A}{\type{U}}{\type{L}}}}{C}{\ol{T}}) = \emptyset
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%TODO
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\end{gather}
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\begin{gather}
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\Delta', \Delta \vdash [\ol{T}/\ol{\type{A}}]\ol{L} <: \ol{T} \\
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\Delta', \Delta \vdash \ol{T} <: [\ol{T}/\ol{\type{X}}]\ol{U} \\
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\label{rp:3}
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\text{fv}(\ol{T}) \subseteq \text{dom}(\Delta, \overline{\wildcard{B}{U}{L}}) \\
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\label{rp:4}
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\text{dom}(\overline{\wildcard{B}{U}{L}}) \cap \text{fv}(\wctype{\ol{\wildcard{A}{U}{L}}}{C}{\ol{T}}) = \emptyset
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\text{dom}(\overline{\wildcard{B}{U}{L}}) \cap \text{fv}(\wctype{\ol{\wildcard{A}{U}{L}}}{C}{\ol{T}}) = \emptyset\\
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[\ol{A}/\ol{T}] = \ol{T} %TODO: rename T
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\end{gather}
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\ref{rp:4} is always true.
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Due to $\text{fv}(\sigma(\wctype{\overline{\wildcard{B}{\type{U}}{\type{L}}}}{C}{\ol{S}})) = \emptyset$ implies \ref{rp:3}.
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We know
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\begin{gather}
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\ol{S} = [\ol{\wtv{a}}/\ol{A}]\ol{T}\\
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\text{fv}(\wctype{\overline{\wildcard{B}{\type{U'}}{\type{L'}}}}{C}{\ol{S}}) = \emptyset\\
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\label{rp:fv2}
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\text{fv}(\wctype{\overline{\wildcard{A}{\type{U}}{\type{L}}}}{C}{\ol{T}}) = \emptyset
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%TODO
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\end{gather}
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\ref{rp:fv2} implies \ref{rp:4}.
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Due to $\text{fv}(\sigma(\wctype{\overline{\wildcard{B}{\type{U}}{\type{L}}}}{C}{\ol{S}})) = \emptyset$ implies
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$\text{fv}(\type{T}) \subseteq \text{dom}(\overline{\wildcard{B}{\type{U}}{\type{L}}})$
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and therefore \ref{rp:3}.
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\item[Capture]
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If $\text{fv}(\wctype{\Delta}{C}{\ol{T}}) = \emptyset$ the preposition holds by Assumption and S-Exists.
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